Asked by Joy
A piece of copper ball of mass 20g at 200°c is placed in a copper calomiter of mass 60g containing 50g of water at 30°c ignoring heat losses.calculate the final steady temperature of the mixture
Answers
Answered by
Damon
You not only want us to do the problem for you, you want me to Google the specific heat of copper and water. LOL
20 Cc (200 - T) = 60 Cc(T-30)+50Cw(T-30)
20 Cc (200 - T) = 60 Cc(T-30)+50Cw(T-30)
Answered by
faleye
Yes
Answered by
faisat
No
Answered by
Abraham
Please solve the above question
Answered by
Katelyn
I need a worked out solution for this question
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