Asked by Anonymous
                A piece of copper ball of mass 20 gram at 200 degree celcius is place in a copper calorimeter of mass 60 gram containing 50 grm of water at 30 degree celcius, ignoring heat loses calculate the final steady temperature of the mixture. ( S. H. C of water is 4200j/kgk )
            
            
        Answers
                    Answered by
            Damon
            
    .020 Cc (200 - T) = (.060 Cc + .050*4200) (T-30)
where Cc is specific heat of copper in J/kg deg C
    
where Cc is specific heat of copper in J/kg deg C
                    Answered by
            Sunday Isaac
            
    help me solve the question above
    
                    Answered by
            Sunday Isaac
            
    A piece of copper ball of mass 20gram at 200degrees Celsius is placed in the copper calorimeter of mass 60gram containing 50gram of water at 30degrees Celsius ignoring it losses calculated the final stages of temperature. take it specific heat capacity of water 4200Jkg k, specific heat capacity of copper is 400Jkgk
solution
    
solution
                    Answered by
            Abraham Yeaten 
            
    Good for research please help me solve the above problem
    
                    Answered by
            Fariah
            
    I want the solution
    
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