Asked by POPPY
A piece of copper of mass 40g at 200°C is placed in a copper calorimeter of mass 60g containing 50g of water at 10°C. Ignoring heat losses, what will be the final steady temperature after stirring.
(Specific heat capacity of copper= 0.4J/g°C, specific heat capacity of water= 4.2J/g°C)?
(Specific heat capacity of copper= 0.4J/g°C, specific heat capacity of water= 4.2J/g°C)?
Answers
Answered by
bobpursley
The sum of the heats gained is zero.
heatgainedcopper+heat gained calorimeter+heat gained water=0
40*.4*(Tf-200)+60*.4*(Tf-10)+50*4.2*(Tf-10)=0
solve for Tfinal Tf
heatgainedcopper+heat gained calorimeter+heat gained water=0
40*.4*(Tf-200)+60*.4*(Tf-10)+50*4.2*(Tf-10)=0
solve for Tfinal Tf
Answered by
B.O.B
Wishing it could be solved
Answered by
Kasita yusuf
Please help me with that question i want the answer
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