Question

A piece of copper of mass 300 g at a temperature of 950 degree Celsius is quickly transferred to a vessel of negligible thermal containing 250 g of water at 25 degree Celsius. If the final temperature of the mixture is 100 degree Celsius calculate the mass of the water that will boil away ( specific heat capacity of copper =400 j/kg.k specific latent heat of vaporization of steam =2260000jkg

Answer 1

0.300 * 400 * (950-100) = 102,000 Joules lost by copper

that heats 0.250 kg water to 100 from 25
0.250 * 4186 * 75 = 78488 Joules used from copper to heat water.
That leaves 23,512 Joules to boil water
23,512 = m 2,260,000
m = .0104 kg = 10.4 grams

Answer 2

Thanks

Answer 3

What if the special heat capacity of water is 4.2×10^2

Answer 4

Where is the 4186 from

Answer 5

Yes

Answer 6

Where is the 4186 from? i am confused

Answer 7

That not the answer

Answer 8

i dont even understand this solving sef

Answer 9

I don't understand the solving