Asked by Arthur

Quadrant III, csc(theta)= -1.25, find tan(theta)
Quadrant IV, sec(theta)= 4/3, find cot(theta)

Please provide the work for both. Thank you!
Answered by Reiny
I will do the first one, you do the second.

csc(theta) = -1.25 = -5/4 and we are in III
so sin(theta) = -4/5

construct your right-angles triangle, and since sin(theta) = y/r
y = -4, r = 5 and x = ???
x^2 + (-4)^2 = 5^2
x = -3 since we are in quadrant III

tan(theta) = -3/5
Answered by Arthur
For the second problem, I got 4squareroot7/7
Answered by Steve
not quite -- 4/√7 is cscθ
did you draw the triangle?
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