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Asked by maggie

Find the area of the region enclosed by the parametric equation x = t^3−3t y = 6t^2.
8 years ago

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Answered by Steve
The loop is formed when x=0, or t=±√3

So, the area is

∫[-√3,√3] y(t) dx/dt dt
= ∫[-√3,√3] (6t^2)(3t^2-3) dt = 144√3/5


8 years ago
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Find the area of the region enclosed by the parametric equation x = t^3−3t y = 6t^2.

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