Ask a New Question

Asked by Abdullah

Find the area of the region between the curves y=lnx and y=ln2x from x=1 and x=5.
8 years ago

Answers

Answered by Steve
∫[1,5] (ln2x - lnx) dx
= ∫[1,5] ln2+lnx-lnx dx
= ∫[1,5] ln2 dx
= 4ln2
8 years ago
Answered by harsha
thanks bro
3 years ago

Related Questions

a) Find the area of the region R bounded by the graphs of the equations y=2x−x^2, x=0, and y=0. b... Find the area of the region that lies inside the first curve and outside the second curve. r = 1 +... Find the area of the region. Please show work so I can understand. 2y=5x^(1/2),y=3,2y+4x=9 Find the area of the region RR bounded by y=sin(x), y=cos(x), x=−π/3, x=13/6. Find the area of the region bounded by the graphs of y = −x2 + 3x + 4 and y = 4. a) 2.7 b) 4.5... Find the area of the region bounded by the curves y = sin x, y = csc^2x, x = pi/4, and x = (3pi)/4. Find the area of the region that lies outside the circle x^2 + y^2 = 4 but inside the circle x^2 +... Find the area of the region bounded by y = x^2 + 2x -6 and y = 3x. Find the area of the region enclosed between and from to . Hint: Notice that this region consists...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use