I read that as
f(x) = x^2 - x - 6x^2 - 8x + 15
= -5x^2 -9x + 15
-5x^2 -9x + 15 = 0
5x^2 + 9x - 15 = 0
use the quadratic formula to solve.
Both zeros are irrational
Somehow I suspect you have a typo in your equation.
What is the zero of the function?
f(x)=x2−x−6x2−8x+15
Enter your answer in the box.
-2
3 answers
Use a graphing calculator or other technology to answer the question.
Which quadratic regression equation best fits the data set?
A. yˆ=0.728x2+20.213x+179.246
B. yˆ=0.728x2−20.213x+179.246
C. yˆ=179.246x2−20.213x+0.728
D. yˆ=0.728x2+0.564x+179.246
x y
4 109
6 88
9 52
15 42
18 50
21 78
23 98
Which quadratic regression equation best fits the data set?
A. yˆ=0.728x2+20.213x+179.246
B. yˆ=0.728x2−20.213x+179.246
C. yˆ=179.246x2−20.213x+0.728
D. yˆ=0.728x2+0.564x+179.246
x y
4 109
6 88
9 52
15 42
18 50
21 78
23 98
The answer is D.yˆ=0.728x^2−20.213x+179.246
Took the test, that's correct
Took the test, that's correct