let x^2 - 18x - 4 = 0
best done by completing the square
x^2 - 18x + 91 = 4 + 81
(x-9)^2= 85
x - 9 = √85
x = 9 ± √85
Your question should have said
"What are the zeros of ...." , since there are two of them.
What is the zero of the function x^2-18x-4
1 answer
1 answer