Asked by Apexya
For what value of x the function f(x)=(4x+7)÷(x^2-2x)
Answers
Answered by
Henry
F(x) = (4x+7) + (x^2-2x).
F(x) = Y = x^2 + 2x + 7.
X = -B/2A = -2/2 = -1.
Y = (-1)^2 + 2(-1) + 7 = 6.
Min. point: (x,y) = (-1,6).
F(x) = Y = x^2 + 2x + 7.
X = -B/2A = -2/2 = -1.
Y = (-1)^2 + 2(-1) + 7 = 6.
Min. point: (x,y) = (-1,6).
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