Asked by Elizabeth

Assume you are speeding down the freeway at 75 mph. The car weighs 1500 kg and the effective force of the brakes is 14400 N. The car in front of you suddenly slows down, it takes 3 seconds for the car to do so. Your initial velocity was 33.53 and your final velocity is 0. If your reaction time is 1.6 seconds, how long would it take to slow down? In meters and seconds.

Answers

Answered by Steve
(e<sup><sup>2x</sup></sup>)<sup><sup>1/x</sup></sup> < (x+e<sup><sup>x</sup></sup>+e<sup><sup>2x</sup></sup>)<sup><sup>1/x</sup></sup> < (2e<sup><sup>2x</sup></sup>)<sup><sup>1/x</sup></sup>
Answered by Steve
(e<sup><sup>2x</sup></sup>)<sup><sup>1/x</sup></sup> < (x+e<sup><sup>x</sup></sup>+e<sup><sup>2x</sup></sup>)<sup><sup>1/x</sup></sup> < (2e<sup><sup>2x</sup></sup>)<sup><sup>1/x</sup></sup>

e(<sup><sup>2</sup></sup> < (x+e<sup><sup>x</sup></sup>+e<sup><sup>2x</sup></sup>)<sup><sup>1/x</sup></sup> < 2<sup><sup>1/x</sup></sup>e<sup><sup>2</sup></sup><sup><sup>1/x</sup></sup>
Answered by Steve
(e<sup><sup>2x</sup></sup>)<sup><sup>1/x</sup></sup> < (x+e<sup><sup>x</sup></sup>+e<sup><sup>2x</sup></sup>)<sup><sup>1/x</sup></sup> < (2e<sup><sup>2x</sup></sup>)<sup><sup>1/x</sup></sup>

e<sup><sup>2</sup></sup> < (x+e<sup><sup>x</sup></sup>+e<sup><sup>2x</sup></sup>)<sup><sup>1/x</sup></sup> < 2<sup><sup>1/x</sup></sup>e<sup><sup>2</sup></sup>
Answered by Steve
(e<sup><sup>2x</sup></sup>)<sup><sup>1/x</sup></sup> < (x+e<sup><sup>x</sup></sup>+e<sup><sup>2x</sup></sup>)<sup><sup>1/x</sup></sup> < (2e<sup><sup>2x</sup></sup>)<sup><sup>1/x</sup></sup>

e<sup><sup>2</sup></sup> < (x+e<sup><sup>x</sup></sup>+e<sup><sup>2x</sup></sup>)<sup><sup>1/x</sup></sup> < 2<sup><sup>1/x</sup></sup>e<sup><sup>2</sup></sup>

Now take the limits, and since 2<sup><sup>1/x</sup></sup>-> 1,

e<sup><sup>2</sup></sup> < (x+e<sup><sup>x</sup></sup>+e<sup><sup>2x</sup></sup>)<sup><sup>1/x</sup></sup> < e<sup><sup>2</sup></sup>

so

(x+e<sup><sup>x</sup></sup>+e<sup><sup>2x</sup></sup>)<sup><sup>1/x</sup></sup> = e<sup><sup>2</sup></sup>
Answered by Steve
      sinx(cosx-sinx)
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sinx(cosx+sinx)(cosx-sinx)
Answered by Steve
        sinx(cosx-sinx)
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sinx(cosx+sinx)(cosx-sinx)
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