a car is speeding up and has an instantaneous velocity of 6.0 m/s in the x direction when a stopwatch reads 10.0 s. it has a constant acceleration of 1.5 m/s^2 in the x direction until the stopwatch 12.0 s. how far does it travel during this time interval?

Answer 1

call t=0 when the stopwatch reads 10. Then for the next two seconds, starting with initial velocity of 6,

s(t) = 6t + .75t^2
s(2) = 6*2 + .75*4 = 15.0m