Asked by TiffTaff
A car is speeding at 25 m/s in a school zone. A police car starts from rest just as the speeder passes and accelerates at a constant rate of 5 m/s2. How fast is the police car traveling when it is 25 m behind the speeding car?
I honestly don't know where to start. We don't know the final velocity (we're trying to find it, duh) and since we don't have the time, I don't know what to do.
Thanks.
I honestly don't know where to start. We don't know the final velocity (we're trying to find it, duh) and since we don't have the time, I don't know what to do.
Thanks.
Answers
Answered by
bobpursley
you know the distance both cars went in the same time
d1=25*t
d1-25=1/2 5(t^2) then
25t-25=2.5 t^2
solve for time t, then how fast is ...
v=5t
d1=25*t
d1-25=1/2 5(t^2) then
25t-25=2.5 t^2
solve for time t, then how fast is ...
v=5t
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