Question
A car is speeding at 33.4 m/s. A police car starts in pursuit from rest when the car is 100 m past the cruiser. At what rate must the cruiser accelerate to catch the speeder before the state line, 1.2 km away from the speeding car?
Include all steps if possible please, so that I may fully understand.
Include all steps if possible please, so that I may fully understand.
Answers
d = r*t = 1200 m.
33.4t = 1200,
t = 1200 / 33.4 = 35.93 s. = Time to reach state line.
Dt = 100 + 1200 = 1300 m. = Dist. the
trooper must travel to reach state line.
Dt = 0.5a*t^2 = 1300 m.
0.5a*(35.93)^2 = 1300,
0.5a*1291 = 1300,
645.5a = 1300,
a = 1300 / 645.5 = 2.014 m/s^2.
33.4t = 1200,
t = 1200 / 33.4 = 35.93 s. = Time to reach state line.
Dt = 100 + 1200 = 1300 m. = Dist. the
trooper must travel to reach state line.
Dt = 0.5a*t^2 = 1300 m.
0.5a*(35.93)^2 = 1300,
0.5a*1291 = 1300,
645.5a = 1300,
a = 1300 / 645.5 = 2.014 m/s^2.
Related Questions
A car
speeding at
30km/hr passes a
police car at rest
just at the
speeding
motorist passes
th...
A car travelling 19.4m/s passes apolice car at rest.As it passes, the police car starts up, accelera...
A car is speeding at 25 m/s in a school zone. A police car starts from rest just as the speeder pass...
A speeding motorist passes a parked police car at a constant straight-line speed of 110kmh^-1
in a...