Asked by sam
during the takeoff roll, a boeing 747 jumbo jet is accelarating at 4m\s. it requires 40 s to reach takeoff speed. what is the initial velocity of the jet?
Answers
Answered by
Henry
V2 = a*t = 4 * 40 = 160 m/s = Take-off speed.
V2 = V1 + a*t.
160 = V1 + 4*40, V1 = 0.
V2 = V1 + a*t.
160 = V1 + 4*40, V1 = 0.
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