Asked by Karina
At takeoff a commercial jet has a 65.0 m/s speed. Its tires have a diameter of 0.700 m.
(a) At how many rpm are the tires rotating?
Incorrect: Your answer is incorrect.
rpm
(b) What is the centripetal acceleration at the edge of the tire?
Incorrect: Your answer is incorrect.
m/s2
(c) With what force must a determined 10-15 kg bacterium cling to the rim?
N
(d) Take the ratio of this force to the bacterium's weight.
(force from part (c) / bacterium's weight)
(a) At how many rpm are the tires rotating?
Incorrect: Your answer is incorrect.
rpm
(b) What is the centripetal acceleration at the edge of the tire?
Incorrect: Your answer is incorrect.
m/s2
(c) With what force must a determined 10-15 kg bacterium cling to the rim?
N
(d) Take the ratio of this force to the bacterium's weight.
(force from part (c) / bacterium's weight)
Answers
Answered by
Steve
(a)
65.0 m/s * 1rev/.700π m = 29.557 rev/s
65.0 m/s * 1rev/.700π m = 29.557 rev/s
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