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Asked by paul

During takeoff, an airplane, climbs with a speed of 180 m/s at an angle of 34ยบ above the horizontal. The sun is shining directly overhead. How fast is the shadow of the plane moving along the ground? (That is, what is the magnitude of the horizontal component of the plane's velocity?)

12 years ago

Answers

Answered by Henry
Xo = 180*cos34 = 149.2 m/s.
12 years ago
Answered by Anonymous
12342
10 years ago
Answered by lolo
Xo = 180*cos34 = 149.2 m/s
7 years ago

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