Asked by paul

During takeoff, an airplane, climbs with a speed of 180 m/s at an angle of 34º above the horizontal. The sun is shining directly overhead. How fast is the shadow of the plane moving along the ground? (That is, what is the magnitude of the horizontal component of the plane's velocity?)

12 years ago

Answered by Henry

Xo = 180*cos34 = 149.2 m/s.

12 years ago

Answered by Anonymous

12342

10 years ago

Answered by lolo

Xo = 180*cos34 = 149.2 m/s

7 years ago

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