Question
The position of a particle moving along the x-axis as a function of time,t, is given by x(t)=(1/6)t^3-t^2+3t-1 for t≥0. The particle's velocity becomes three times its initial velocity when t=?
I know v(t)=x'(t)=(1/2)t^2-2t+3=9, but I do not understand where does the 9 come from.
Some help would be appreciated, thanks.
I know v(t)=x'(t)=(1/2)t^2-2t+3=9, but I do not understand where does the 9 come from.
Some help would be appreciated, thanks.
Answers
read the question carefully.
v(0) = 3
you want v to be three times its initial value. 3*3 = 9
v(0) = 3
you want v to be three times its initial value. 3*3 = 9
Related Questions
The function ax(t) describes the acceleration of a particle moving along the x-axis. At time t=0,...
The position function x(t) of a particle moving along an x axis is x = 6.00 - 8.00t2, with x in mete...
The position of a particle moving along the x-axis at time t > 0 seconds is given by the function...
The position of a particle moving along the x-axis is given by the function f(t)=4t3−39t2+108t . Dur...