Question

The position of a particle moving along the x axis is given by x= 12t2 -2t ,where x is in meters and t in seconds . determine the velocity and the acceleration of the particle at t=3.0s

Answer 1

well, you have
x = 12t^2 - 2t
v = x' = 24t - 2
a = v' = 24
so plug in your numbers

Answer 2

X = 12T^2 - 2T
X = 12*3^2 - 2*3 = 102 m.
V = x/T = 108m/3s = 36 m/s.

V = a*T
36 = a*3
a =