Asked by zizi
the position of a particle moving along a coordinate line is s=√(1+4t) , with s in metres and t in seconds. Find the particle's velocity and acceleration at t=6 sec
Answers
Answered by
Steve
v = ds/dt = 2/√(1+4t)
a = dv/dt = -4/(1+4t)<sup>3/2</sup>
now just plug in t=6
a = dv/dt = -4/(1+4t)<sup>3/2</sup>
now just plug in t=6
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