Asked by Kimora
A constant force of 40 N is applied tangentially to the rim of a wheel with 20 cm radius.
The wheel has a moment of inertia of 30 kg m2.
Show that the angular acceleration of
the wheel is 0.27 rad s-2
The wheel has a moment of inertia of 30 kg m2.
Show that the angular acceleration of
the wheel is 0.27 rad s-2
Answers
Answered by
bobpursley
Torque=I*alpha
force*radius=I(alpha
solve for alpha.
force*radius=I(alpha
solve for alpha.
Answered by
Kimora
oo...i totally forgot to expand torque to be the force x perpend. radius
thanks..got it
thanks..got it
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