Asked by katie
A constant net force of 385 N is applied upward to a stone that weighs 28 N. The upward force is applied through a distance of 2.0 m, and the stone is then released. To what height, from the point of release, will the stone rise?
what formula(s) do i use?
what formula(s) do i use?
Answers
Answered by
drwls
This question was answered elsewhere. If you assume the net force includes the weight, multiply 385 N by 2.0 m to get the kinetic energy when it is released. Call that K.E.= 770 J
Then use K.E = M g h = W h
to get the additional height H that it rises after release. W is the weight in Newtons.
In one step,
h = (net force)*(2.0 m)/W
Then use K.E = M g h = W h
to get the additional height H that it rises after release. W is the weight in Newtons.
In one step,
h = (net force)*(2.0 m)/W
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