Question
A constant net force of 20 N is applied to a 32 kg car, causing it to speed up from 4.0 to 9.0 m/s. How long is the force applied?
Answers
DrBob222
This is chemistry???
Anonymous
If there is no friction then
a = F/m = 20/32 = 0.625 meters/ second^2
v = initial velocity + a t
9 = 4 + 0.625 t
t = 5 / 0.625 = 8 seconds
a = F/m = 20/32 = 0.625 meters/ second^2
v = initial velocity + a t
9 = 4 + 0.625 t
t = 5 / 0.625 = 8 seconds