A constant net force of 406 N, up, is applied to a stone that weighs 33 N. The upward force is applied through a distance of 2.4 m, and the stone is then released. To what height, from the point of release, will the stone rise?

Question

A constant net force of 406 N, up, is applied to a stone that weighs 33 N.  The upward force is applied through a distance of 2.4 m, and the stone is then released.  To what height, from the point of release, will the stone rise?

Thoughts: F = ma.  Would the acceleration be g?  You would divide the weight by g to get the mass of the stone, correct?

drwls · Answer

The acceleration a is given by a = F/m = 12.30 m/s^2 The velocity when released is V = sqrt (2aX) = 7.68 m/s The height H that it reaches after that is given by gH = V^2/2 H = V^2/(2g)