Asked by Einstein
A constant net force of 406 N, up, is applied to a stone that weighs 33 N. The upward force is applied through a distance of 2.4 m, and the stone is then released. To what height, from the point of release, will the stone rise?
Thoughts: F = ma. Would the acceleration be g? You would divide the weight by g to get the mass of the stone, correct?
Thoughts: F = ma. Would the acceleration be g? You would divide the weight by g to get the mass of the stone, correct?
Answers
Answered by
drwls
The acceleration a is given by
a = F/m = 12.30 m/s^2
The velocity when released is
V = sqrt (2aX) = 7.68 m/s
The height H that it reaches after that is given by
gH = V^2/2
H = V^2/(2g)
a = F/m = 12.30 m/s^2
The velocity when released is
V = sqrt (2aX) = 7.68 m/s
The height H that it reaches after that is given by
gH = V^2/2
H = V^2/(2g)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.