Asked by Ashley
A baseball player hits a foul ball straight up in the air from a height of 4 feet off the ground with an initial velocity of 85 feet per second.
When is the ball 110 feet off the ground?
When is the ball 110 feet off the ground?
Answers
Answered by
bobpursley
h=4+85*time - 1/2 32*time^2
16time^2-85*time-106=0
use the quadratic formula to solve for time (notice two solutions, one going up, one going back down).
time=(85+-sqrt(85^2+4*16*106) )/32
check that, and solve.
16time^2-85*time-106=0
use the quadratic formula to solve for time (notice two solutions, one going up, one going back down).
time=(85+-sqrt(85^2+4*16*106) )/32
check that, and solve.
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