Question
A baseball player hits a pop fly that goes directly up in the air with an initial velocity of 45 m/s. What is the maximum height the base ball reaches?
Work: initial velocity = 45 m/s, gravity= -9.8 m/s, final velocity = 0 m/s
Work: initial velocity = 45 m/s, gravity= -9.8 m/s, final velocity = 0 m/s
Answers
Henry
Vf^2 = Vo^2 + 2g*h.
h = ?
h = ?