Question

a body of massb20kg slides down a plane inclined at 30degree to the horizontal if a constant resting force of 40N act on the body it acceleration down the plane is what?
f=mgsin
ma=mg sin
20×a=20×10sin30
20a=100
a=50

Answer 1

See previous post.

Answer 2

using F=MA, Mg=Mgsin
in Relation we have;-
M=20kg, F=40N, a=?
:-(a) as subject formula,
:- a=f/m, 40/20=2
mgsin= 2*10sin, 20sin30degree
10.