d=1/2 a t^2
solve for a.
Net force=masstotal*a
9.8(294-M)=(294+M) a
solve for M
a 294 kg crate is released from rest and hits the ground 1.18 m below after 4.10 s. What is the mass of the crate to the left of the pulley? Assume the rope and pulley are massless.
1 answer
0 answers