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a 294 kg crate is released from rest and hits the ground 1.18 m below after 4.10 s. What is the mass of the crate to the left of the pulley? Assume the rope and pulley are massless.
Answers
Answered by
bobpursley
d=1/2 a t^2
solve for a.
Net force=masstotal*a
9.8(294-M)=(294+M) a
solve for M
solve for a.
Net force=masstotal*a
9.8(294-M)=(294+M) a
solve for M
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