The force down the plane is
check me
mgSinTheta, the force of friction is mu*mgCosTheta.
Now what is .25? m/s? You have to put units with numbers, 37 (degrees?), .25 ?
Maybe you meant .25m/s^2
net force= ma
mgsintheta-mu*mgCosTheta=m a
check that, and solve for mu.
A 11.0 box is released on a 37 incline and accelerates down the incline at 0.25 .What is the coefficient of kinetic friction in units uk?
What is the friction force impeding its motion in N?
1 answer