Asked by Mary

The difference of two numbers is 47. The larger number is three less than six times the smaller number. Find the numbers.
Answered by PsyDAG
L = S + 47

L = 6S - 3

Substitute S+47 for L in the second equation and solve for L. Insert that value into the first equation to solve for S. Check by putting both values into the second equation.
Answered by Nun Ya
S+47=6S-3
+3 +3
S+50=6S
-S -S
50= 5S
10=S
L=S+47
L=(10)+47
L=57