Asked by Olivia

If 2 numbers have a difference of 2.38, one number is 3 times bigger than the other number and the two numbers both add up to 6, what could the two numbers be?
Answered by Steve
y-x = 2.38
y = 3x
x+y = 6

You only need two of the equations to solve for x and y.

As it happens, there is no solution to all three conditions:

Using

y-x = 2.38
y = 3x

3x-x = 2.38
2x = 2.38
x = 1.19
y = 3x = 5.37
Fails to satisfy x+y=6

or, using

y-x = 2.38
x+y = 6

2x = 8.38
x = 4.19
y = 1.81
Fails to satisfy y=3x

or, using
y = 3x
x+y = 6

x+3x = 6
4x = 6
x = 1.5
y = 4.5
Fails to satisfy y-x = 2.38
Answered by Charlotte
THERE IS NO SOULITION!
Answered by Random 10 year old stuck with homework
THERE IS NO ANSWER!! IT'S IMPOSSIBLE
Answered by Bob
Ya yeet
:)
Answered by yeet
IT IS IMPOSSIBLE WE HAD THIS QUESTION AT SCHOOL AND NO ONE NOT EVEN THE TEACHERS COULD WORK IT OUT!

Answered by Daivd
It is impossible you divs
Answered by Daivd
Your an idiot
Answered by Tl
bar model
6 - 2.38 = 3.62
3.62 divide by 2 = 1.81

therefore 1.81 plus 4.19 (2.38 + 1.81)
Answered by Tl
If 2 numbers have a difference of 2.38, one number is 3 times bigger than the other number and the two numbers both add up to 6, what could the two numbers be?

If this is in oxf owl mastery - the Q is actually not this -
Q1 = 2 numbers have a difference of 2.38 and the two numbers add up to 6 (see above answer)
Q2 = 2 numbers have a difference of 2.38 but one of the numbers is 3 times bigger than the other (BUT doesn't say have to add to 6)