Asked by Asha

Prove that
Log384/5+log81/32+3log5/3-log9= 2.
Answered by Reiny
LS = Log384/5+log81/32+3log5/3-log9
= Log384/5+log81/32+log5^3/3^3-log9
= log( (384/5)(81/32)(125/27)/9 )
= log(100)
= 2
= RS
Answered by Victor
I need steps to follow of that question