Asked by Logritham

Log384÷5+log81÷32+3log5÷3-log9=2

8 years ago

Answered by Steve

I assume you mean
log(384/5)+log(81/32)+3log(5/3)-log9
=log(384*81*125)/(5*32*27*9)
=log(3888000/38880)
=log 100
= 2

8 years ago

Answers