Question
Find x if 3log5+logx²=log1/125
Answers
oobleck
using the rules of logs, you have
log(5^3 * x^2) = log(1/125)
125x^2 = 1/125
x^2 = 1/(125^2) = 5^-6
x = ±5^-3 = ±1/125
log(5^3 * x^2) = log(1/125)
125x^2 = 1/125
x^2 = 1/(125^2) = 5^-6
x = ±5^-3 = ±1/125