Question
3 log 2+log 20-log1
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Answers
Anonymous
The answer
Anonymous
I assume base 10 logs
log 1 = 0 and log 10 = 1, remember 10^log x = x
lots of ways :)
log 2^3 + log (2*10) - 0
3 log 2 + log 2 + log 10
4 log 2 + 1
log 16 + log10
log 160
2.2
log 1 = 0 and log 10 = 1, remember 10^log x = x
lots of ways :)
log 2^3 + log (2*10) - 0
3 log 2 + log 2 + log 10
4 log 2 + 1
log 16 + log10
log 160
2.2