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3 log2 + log20 - log1.6
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oobleck
log(2^3 * 20 / 1.6) = log 100 = 2
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How do you find log20, if log2=.301?? Please show work
3log2+log20-log1.6
Log20+3log2-lpgq.6
log5 +log20 log√8 ÷ log8
if log2 =0.301 than log20 =?
4log2/log20-log3