Asked by yaga
Find the inverses
1)
y=9/x
x=9/y
xy=9
y=9/x Which is wrong I believe
2)
y=(2x+1)/(3-2x) How do I get rid of the ys after I replace the xs with them?
1)
y=9/x
x=9/y
xy=9
y=9/x Which is wrong I believe
2)
y=(2x+1)/(3-2x) How do I get rid of the ys after I replace the xs with them?
Answers
Answered by
Steve
f^-1(9/x) = 9/x
since
f^-1(f(x)) = 9/(f(x)) = 9/(9/x) = x
swap variables and solve for y:
x = (2y+1)/(3-2y)
x(3-2y) = 2y+1
3x-2xy = 2y+1
3x-1 = 2xy+2y
3x-1 = y(2x+2)
y = (3x-1)/(2x+2)
since
f^-1(f(x)) = 9/(f(x)) = 9/(9/x) = x
swap variables and solve for y:
x = (2y+1)/(3-2y)
x(3-2y) = 2y+1
3x-2xy = 2y+1
3x-1 = 2xy+2y
3x-1 = y(2x+2)
y = (3x-1)/(2x+2)
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