Question
Find the inverses of the following functions.
y = 3(x - 1)^2, x >= 1
Work:
x = 3(y - 1)^2
x = 3(y - 1)(y - 1)
x = 3(y^2 - y - y + 1)
x = 3y^2 - 6y + 3
And now what do I do!? Please explain and show me how to solve this inverse function!
...
Thank you
y = 3(x - 1)^2, x >= 1
Work:
x = 3(y - 1)^2
x = 3(y - 1)(y - 1)
x = 3(y^2 - y - y + 1)
x = 3y^2 - 6y + 3
And now what do I do!? Please explain and show me how to solve this inverse function!
...
Thank you
Answers
x = 3(y - 1)^2 would be the inverse but you forgot the second part, y>=1