Asked by Anonymous
Find the inverses of the following functions.
y = 3(x - 1)^2, x >= 1
Work:
x = 3(y - 1)^2
x = 3(y - 1)(y - 1)
x = 3(y^2 - y - y + 1)
x = 3y^2 - 6y + 3
And now what do I do!? Please explain and show me how to solve this inverse function!
...
Thank you
y = 3(x - 1)^2, x >= 1
Work:
x = 3(y - 1)^2
x = 3(y - 1)(y - 1)
x = 3(y^2 - y - y + 1)
x = 3y^2 - 6y + 3
And now what do I do!? Please explain and show me how to solve this inverse function!
...
Thank you
Answers
Answered by
Damon
x = 3(y - 1)^2 would be the inverse but you forgot the second part, y>=1
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.