Asked by Chelsea Woodard
A ball is thrown upward into the air with a speed of 15m/s. At what times does the ball pass a point 8 meters above the person's hand?
8m=-0.5(9.8)(t)
t=1.8 seconds
Is that correct?
8m=-0.5(9.8)(t)
t=1.8 seconds
Is that correct?
Answers
Answered by
Steve
The ball's height is modeled by
h(t) = 15t - 4.9t^2
The ball will be 8m high twice: on the way up and on the way down. These times can be found by solving
15t - 4.9t^2 = 8
See
http://www.wolframalpha.com/input/?i=15t+-+4.9t%5E2+%3D+8
If you include the units in your equation, you will see that the right side is not in meters...
h(t) = 15t - 4.9t^2
The ball will be 8m high twice: on the way up and on the way down. These times can be found by solving
15t - 4.9t^2 = 8
See
http://www.wolframalpha.com/input/?i=15t+-+4.9t%5E2+%3D+8
If you include the units in your equation, you will see that the right side is not in meters...
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.