Question
A ball is thrown upward from a platform 5.1 meters high with a speed of 13 m/s at an angle 45 degrees from the horizontal. what is the magnitude of its velocity when it hits the ground?
Answers
drwls
No matter what the angle is, the ball will gain kinetic energy M g H, the potential energy decrease. The kinetic energy per mass is V^2/2.
Therefore V^2 will increase by 2gH, from 169 m^2/s^2 to 169 + 2*9.8*5.1 = 269 m^2/s^2.
The new velocity = 16.4 m/s
Therefore V^2 will increase by 2gH, from 169 m^2/s^2 to 169 + 2*9.8*5.1 = 269 m^2/s^2.
The new velocity = 16.4 m/s