A ball is thrown upward with an initial velocity of 13 m/s. At what time does the ball reach the high point in its flight? (Use the approximate value of g = 10 m/s2, and remember that the velocity is equal to zero at the high point.)

Answer 1

use the kinematic equation vf=vi+-9.8T
(-9.8 is the true acceleration due to gravity)
what we know
vf=0
vi=13
g=-9.8
t=x
then just plug and chug answer should be around 1.326 s