Asked by Cora
Hi! I was wondering if anyone might be willing to check my answers for these... I have a suspiscion they are wrong, but I don't have any correct answers to compare them against. If I got them wrong, would you mind giving a brief explanation? Thank you for your help! (x^2-1)+(-2x+3) (I got 2x+x^2+2).
(X^2-1) (x^2+-9) (I got x^3+-12)
(x^2+-9)-(x+-3) (I got x+12)
f(g(x)) F=3x-4 G=(-x^2)I got -3x^3+4x^2
f(g(x))F=-2x G+-2x^2+3 I got 4x^3+-6x
(X^2-1) (x^2+-9) (I got x^3+-12)
(x^2+-9)-(x+-3) (I got x+12)
f(g(x)) F=3x-4 G=(-x^2)I got -3x^3+4x^2
f(g(x))F=-2x G+-2x^2+3 I got 4x^3+-6x
Answers
Answered by
drwls
Your answers almost seem like wild guesses. You appear to be in serious need of private tutoring until you grasp basic algebraic rules.
Why do you have both a + and- in front of the 9 in the first problem and in front of the 3 in the second problem?
(x^2-1) (x^2-9) = x^4 - 10x^2 +9
x^2 -9 -(x -3) = x^2 -x -6
If f=3x-4 and g=(-x^2)
f[g(x)] = -3x^2 -4
g[f(x)] = -(3x-4)^2 =-9x^2 +24x -16
Why do you have both a + and- in front of the 9 in the first problem and in front of the 3 in the second problem?
(x^2-1) (x^2-9) = x^4 - 10x^2 +9
x^2 -9 -(x -3) = x^2 -x -6
If f=3x-4 and g=(-x^2)
f[g(x)] = -3x^2 -4
g[f(x)] = -(3x-4)^2 =-9x^2 +24x -16
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