Asked by Karla
                Hey :)
I was wondering if someone could tell me if this answer and working is correct or not...
Cos theta =-0.25
Cos inverse -0.25 = -14
therefore theta equals:
180--14=194or/and
180+-14=166
Any help would be much appreciated :)
Thanks!
            
        I was wondering if someone could tell me if this answer and working is correct or not...
Cos theta =-0.25
Cos inverse -0.25 = -14
therefore theta equals:
180--14=194or/and
180+-14=166
Any help would be much appreciated :)
Thanks!
Answers
                    Answered by
            Jai
            
    cos (theta) = -0.25
theta = cos^-1 (-0.25)
there are two answers:
theta = 104.48 degrees = 3.65 radians
and,
theta = -104.48 degrees = -3.65 radians
hope this helps~ :)
    
theta = cos^-1 (-0.25)
there are two answers:
theta = 104.48 degrees = 3.65 radians
and,
theta = -104.48 degrees = -3.65 radians
hope this helps~ :)
                    Answered by
            Reiny
            
    Usually the required angles are in the domain of
0 ≤ Ø ≤ 360°
Since the given cosØ is negative, by the CAST rule,
Ø must be in either quadrant II or III
from cosØ = +.25 we get the reference angle of 75.52°
so Ø = 180°-75.52° or 104.48° (Jai's answer)
or Ø = 180°+75.52° or 255.52°
Since the period of cosØ is 360°, you can get other answers by adding or subtracting multiples of 360°
(For Jai's second answer, 255.52 - 360° = 104.48°)
I have no idea how you came up with
inverse cos (-.25) = -14
    
0 ≤ Ø ≤ 360°
Since the given cosØ is negative, by the CAST rule,
Ø must be in either quadrant II or III
from cosØ = +.25 we get the reference angle of 75.52°
so Ø = 180°-75.52° or 104.48° (Jai's answer)
or Ø = 180°+75.52° or 255.52°
Since the period of cosØ is 360°, you can get other answers by adding or subtracting multiples of 360°
(For Jai's second answer, 255.52 - 360° = 104.48°)
I have no idea how you came up with
inverse cos (-.25) = -14
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