Asked by sarah
i was wondering if i did this right
A cannon ball is shot from a cannon on top of a hill that is 73.5 meters above sea level. The cannon ball leaves the cannon with a velocity of 9.8 m/s. Write and solve a quadratic equation to determine when the cannon ball will reach sea level.
0 = -4.9t² + 9.8t + 73.5
0 = -4.9(t² - 2t - 15)
0 = -4.9(t - 5)(t + 3)
t - 5 = 0 and t + 3 = 0
t = {5,-3}
t = 5 since t = -3 is not acceptable negative value.
Hence, the cannon ball will reach sea level at 5 seconds.
A cannon ball is shot from a cannon on top of a hill that is 73.5 meters above sea level. The cannon ball leaves the cannon with a velocity of 9.8 m/s. Write and solve a quadratic equation to determine when the cannon ball will reach sea level.
0 = -4.9t² + 9.8t + 73.5
0 = -4.9(t² - 2t - 15)
0 = -4.9(t - 5)(t + 3)
t - 5 = 0 and t + 3 = 0
t = {5,-3}
t = 5 since t = -3 is not acceptable negative value.
Hence, the cannon ball will reach sea level at 5 seconds.
Answers
Answered by
bobpursley
yes, assuming it was shot horizontally.
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