Asked by sarah
i was wondering what did i do wrong in this
10. Divide (3x – 2)(x - 4) – (x - 4)(6 – 5x) / (4 – x)(8x – 1)
10- (3x-2)(x-4)-(x-4)(6-5x)/(4-x)(8x-1)
The (x-4) cancels out because the (x-4)is common in all the terms of the top and bottom
[(3x-2)]-[(6-5x)]/-(8x-1)
3x+5x=8x
-2-(-6)=-8
8x-8/-(8x-1)
8x-8 factored = 8(x-1)
8(x-1)/-(8x-1) = -1+7/8x-1
10. Divide (3x – 2)(x - 4) – (x - 4)(6 – 5x) / (4 – x)(8x – 1)
10- (3x-2)(x-4)-(x-4)(6-5x)/(4-x)(8x-1)
The (x-4) cancels out because the (x-4)is common in all the terms of the top and bottom
[(3x-2)]-[(6-5x)]/-(8x-1)
3x+5x=8x
-2-(-6)=-8
8x-8/-(8x-1)
8x-8 factored = 8(x-1)
8(x-1)/-(8x-1) = -1+7/8x-1
Answers
Answered by
Reiny
Picking up from
[(3x-2)]-[(6-5x)]/-(8x-1) , which is correct up to there
= (8x - 8)/(1-8x)
= 8(x-1)/(1-8x)
nothing else can be done
[(3x-2)]-[(6-5x)]/-(8x-1) , which is correct up to there
= (8x - 8)/(1-8x)
= 8(x-1)/(1-8x)
nothing else can be done
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