Asked by joel

Prove That Sin2A+SIN2B+SIN2C/SINA+SINB+SINC=8SinA/2SINB/2SINC/2

Answers

Answered by Steve
try using the sum-to-product formulas. If you get stuck, come on back and I'll see what we can do with what you have so far.

I see google has some good discussions.
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