Asked by Collins
Prove that (1-sinb)/(1+sin2b)=tan^2(45-b) plz the b means beta???
Answers
Answered by
Steve
tan 45-b = (tan45-tanb)/(1+tan45 tanb)
= (1-tanb)/(1+tanb)
square that, and you have
(1-2tanb+tan^2b)/(1+2tanb+tan^2b)
= (sec^2b-2tanb)/(sec^2b+2tanb)
= (1/cos^2b - 2sinb/cosb)(1/cos^2b + 2sinb/cosb)
= (1-2sinb cosb)/(1+2sinb cosb)
= (1-sin2b)/(1+sin2b)
I think you have a typo in yours, no?
And why does b have to mean beta? b is just as good.
= (1-tanb)/(1+tanb)
square that, and you have
(1-2tanb+tan^2b)/(1+2tanb+tan^2b)
= (sec^2b-2tanb)/(sec^2b+2tanb)
= (1/cos^2b - 2sinb/cosb)(1/cos^2b + 2sinb/cosb)
= (1-2sinb cosb)/(1+2sinb cosb)
= (1-sin2b)/(1+sin2b)
I think you have a typo in yours, no?
And why does b have to mean beta? b is just as good.
Answered by
Abhishek
4cosacosbsinc
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