Question

f(a)=sin2a(10^sin2a). find f'(a)

Answer 1

use the product and chain rules
f'(a) = 2cos2a * 10^sin2a + sin2a * ln10 * 10^sin2a * 2a cos2a
= 2cos2a * 10^(sin2a) (1 + ln10 sin2a)