Asked by jack
f(a)=sin2a(10^sin2a). find f'(a)
Answers
Answered by
oobleck
use the product and chain rules
f'(a) = 2cos2a * 10^sin2a + sin2a * ln10 * 10^sin2a * 2a cos2a
= 2cos2a * 10^(sin2a) (1 + ln10 sin2a)
f'(a) = 2cos2a * 10^sin2a + sin2a * ln10 * 10^sin2a * 2a cos2a
= 2cos2a * 10^(sin2a) (1 + ln10 sin2a)
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