Asked by Morgan
A 15kg object takes 26.3 meters to stop because of friction. Assume no skidding. If the frictional force is 60 N, what is the initial velocity of the object?
Answers
Answered by
Scott
the work done in stopping is... f * d
... 60 * 26.3 = ? J
the work equals the initial kinetic energy of the object... ½ m v²
60 * 26.3 = ½ * 15 * v²
v = √(8 * 26.3) m/s
be aware of significant figures...
... 60 * 26.3 = ? J
the work equals the initial kinetic energy of the object... ½ m v²
60 * 26.3 = ½ * 15 * v²
v = √(8 * 26.3) m/s
be aware of significant figures...
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