Question
An object travels 50 meters at 90° in 6 seconds and then travels 50 meters at 245° in 13 seconds.
(a) What is the magnitude of the objects resultant displacement?
(b) What is the direction of the objects resutlant displacement?
(c) What is the magnitude of the objects average velocity?
I think I keep getting the wrong direction.
(a) What is the magnitude of the objects resultant displacement?
(b) What is the direction of the objects resutlant displacement?
(c) What is the magnitude of the objects average velocity?
I think I keep getting the wrong direction.
Answers
Damon
x displacement = 50 cos 90 + 50 cos 245
= 0 -21.43
y displacement = 50 sin 90 + 50 sin 245
= 50 -45.3 = 4.68
displacement = sqrt (-21.4^2+ +4.68^2)
= 21.9 meters
x is negative and y is positive so quadrant 2
tan angle above x axis = tan^-1 y/-x = tan^-1 4.68/21.43
= 12.3 deg above - x axis
180 - 12.3 = 168 degrees
moves 21.9 meters displacement in 19 seconds
so 1.15 m/s
= 0 -21.43
y displacement = 50 sin 90 + 50 sin 245
= 50 -45.3 = 4.68
displacement = sqrt (-21.4^2+ +4.68^2)
= 21.9 meters
x is negative and y is positive so quadrant 2
tan angle above x axis = tan^-1 y/-x = tan^-1 4.68/21.43
= 12.3 deg above - x axis
180 - 12.3 = 168 degrees
moves 21.9 meters displacement in 19 seconds
so 1.15 m/s